L(1+x^2)-1=0

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Solution for L(1+x^2)-1=0 equation: 



(1+L^2)-1=0

We get rid of parentheses

L^2+1-1=0

We add all the numbers together, and all the variables

L^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$L=\frac{-b}{2a}=\frac{0}{2}=0$

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